Postingan
TUGAS 20 OKTOBER 22 PRODUKTIF Richan
1. 100.0.0.0/10 Tentukan : -blok subnet -netmask -jumlah subnet -jumlah host/subnet -jumlah host valid -Rentangkan ip pada seluruh subnet JAWAB -11111111.11 000000.00000000.00000000 Blok subnet 256 -192 = 64 Jumlah subnet 2^2 = 4 Jumlah host 2^22 = 4.192.304 Jumlah host valid 2^y - 2 = 4.194.304 - 2 = 4.194.302 rentang ip = 0,64,128,192,256 Network : 100.0.0.0 I : 100.0.0.1 Address : 100.63.255.254 BC : 100.63.255.255 Network : 100.64.0.0 I : 100.64.0.1 Address : 100.127.255.254 BC : 100.127.255.255 Network : 100.128.0.0 I : 100.128.0.1 Address : 100.191.255.254 BC : 100.191.255.255 Network : 100.192.0.0 I : 100.192.0.1 Address : 100.255.255.254 BC : 100.255.255.255 Netmask : •256 - 2y = 256 - 2^6 = 256 - 64 = 192
