TUGAS 20 OKTOBER 22 PRODUKTIF Richan

1. 100.0.0.0/10

Tentukan :

-blok subnet

-netmask

-jumlah subnet

-jumlah host/subnet

-jumlah host valid

-Rentangkan ip pada seluruh subnet

JAWAB

-11111111.11 000000.00000000.00000000

Blok subnet

256 -192 = 64 

Jumlah subnet

2^2 = 4

Jumlah host

2^22 = 4.192.304

Jumlah host valid

2^y - 2 = 4.194.304 - 2 = 4.194.302

rentang ip = 0,64,128,192,256

Network : 100.0.0.0                                        

I : 100.0.0.1

Address : 100.63.255.254

BC : 100.63.255.255

Network : 100.64.0.0

I : 100.64.0.1

Address : 100.127.255.254

BC : 100.127.255.255

Network : 100.128.0.0

 I : 100.128.0.1

Address : 100.191.255.254

BC : 100.191.255.255

Network : 100.192.0.0

 I : 100.192.0.1

Address : 100.255.255.254

 BC : 100.255.255.255

Netmask :

•256 - 2y = 256 - 2^6 = 256 - 64 = 192