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SUBNETTING KELAS B CIDR 20 DAN 23
1. 128.25.0.0/23 2. 128.25.0.0/20 JAWABAN 1 .128.25.0.0/23 11111111.11111111.1111111 0.00000000 a. 256-2y =256-2^1 = 256 -2 = 254 255.255.254.0 B .296-254=2 C .2^Y = 512 D. 2^-2 =2^9 - 2 = 512 -2 =510 SUBNET E. 2^ = 2^7 =128 BIT 0,2,4,8,10,12 BLOK SUBNET SUBNET : 128.25.0.0 HOST : 128.25.0.1 HOST T : 128.25.1.254 BROADCAST :128.25.1.255 ---------------------------------------------- 2. 2. 128.25.0.0/20 IIIIIIII. IIIIIIII. IIII0000. 00000000 A. 256-2^=256-2^=256-16=240 255.255.240.0 B. 256-240=16 C. 2^=4096 D. 2^=2=2^-2=4096-2=4094 HOST F. 2^=2^=16 BIT E. 0,16,32,48,64.....240 BLOK SUBNET SUBNET = 128.25.0....
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